40x^2+20xy=

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Solution for 40x^2+20xy= equation:


Simplifying
40x2 + 20xy = 0

Reorder the terms:
20xy + 40x2 = 0

Solving
20xy + 40x2 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '20x'.
20x(y + 2x) = 0

Ignore the factor 20.

Subproblem 1

Set the factor 'x' equal to zero and attempt to solve: Simplifying x = 0 Solving x = 0 Move all terms containing x to the left, all other terms to the right. Simplifying x = 0

Subproblem 2

Set the factor '(y + 2x)' equal to zero and attempt to solve: Simplifying y + 2x = 0 Reorder the terms: 2x + y = 0 Solving 2x + y = 0 Move all terms containing x to the left, all other terms to the right. Add '-1y' to each side of the equation. 2x + y + -1y = 0 + -1y Combine like terms: y + -1y = 0 2x + 0 = 0 + -1y 2x = 0 + -1y Remove the zero: 2x = -1y Divide each side by '2'. x = -0.5y Simplifying x = -0.5y

Solution

x = {0, -0.5y}

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